scientific notation

scientific notation 1. One of the fundamental equations used in electricity and electronics is Ohm's Law: the relationship between voltage (E or V, measured in units of volts), current (I, measured in units of amperes), and resistance (R, measured in units of ohms): E = IR I = E R R = E I Where, E = Voltage in units of volts (V) I = Current in units of amps (A) R = Resistance in units of ohms () Solve for the unknown quantity (E, I, or R) given the other two, and express your answer in both scientific and metric notations: 1. I = 20 mA, R = 5 k; E = 2. I = 150 µA, R = 47 k; E = 3. E = 24 V, R = 3.3 M; I = 4. E = 7.2 kV, R = 900 ; I = 5. E = 1.02 mV, I = 40 µA; R = 6. E = 3.5 GV, I = 0.76 kA; R = 7. I = 0.00035 A, R = 5350 ; E = 8. I = 1,710,000 A, R = 0.002 ; E = 9. E = 477 V, R = 0.00500 ; I = 10. E = 0.02 V, R = 992,000 ; I = 11. E = 150,000 V, I = 233 A; R = 12. E = 0.0000084 V, I = 0.011 A; R = 13. I = 45 mA, R = 3.0 k; E = 14. I = 10 kA, R = 0.5 m; E = 15. E = 45 V, R = 4.7 k; I = Suppose an electric current of 1.5 microamps (1.5 µA) were to go through a resistance of 2.3 mega-ohms (2.3 M). How much voltage would be "dropped" across this resistance? Show your work in calculating the answer. Solve for Power 1. E = 0.0000084 V, I = 0.011 A; P = 2. I = 45 mA, R = 3.0 k; P= 3. I = 10 kA, R = 0.5 m; P= 4. E = 45 V, R = 4.7 k; P= 5. E = 13.8 kV, R = 8.1 k; P= 6. E = 500 µV, I = 36 nA; P= 7. E = 14 V, I = 110 A; P= 8. I = 0.001 A, R = 922 ; P= 9. I = 825 A, R = 15.0 m; P= 10. E = 1.2 kV, R = 30 M; P=